3y^2-21y+30=0

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Solution for 3y^2-21y+30=0 equation: 



3y^2-21y+30=0

a = 3; b = -21; c = +30;
Δ = b2-4ac
Δ = -212-4·3·30
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-9}{2*3}=\frac{12}{6}
=2
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+9}{2*3}=\frac{30}{6}
=5
$

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